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Don't return reference on copy assignment operators

We prefer to prevent using chained assignment (`T a = b = c = T();`) as this
can lead to confusing code and subtle bugs.

According to https://en.wikipedia.org/wiki/Assignment_operator_(C%2B%2B), C++
allows any arbitrary return type, so this is standard compliant.

This could be re-assessed if/when we have an actual need for a behavior more
akin to that of the C++ STL, for now this PR simply changes a handful of
cases which were inconsistent with the rest of the codebase (`void` return
type was already the most common case prior to this commit).
This commit is contained in:
Rémi Verschelde
2021-11-30 15:19:26 +01:00
parent 2d118bd8b8
commit 7da392bcc5
28 changed files with 93 additions and 90 deletions

View File

@@ -130,9 +130,8 @@ Char16String &Char16String::operator+=(char16_t p_char) {
return *this;
}
Char16String &Char16String::operator=(const char16_t *p_cstr) {
void Char16String::operator=(const char16_t *p_cstr) {
copy_from(p_cstr);
return *this;
}
const char16_t *Char16String::get_data() const {
@@ -186,9 +185,8 @@ CharString &CharString::operator+=(char p_char) {
return *this;
}
CharString &CharString::operator=(const char *p_cstr) {
void CharString::operator=(const char *p_cstr) {
copy_from(p_cstr);
return *this;
}
const char *CharString::get_data() const {