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GDScript: Add CONFUSABLE_CAPTURE_REASSIGNMENT warning
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@@ -0,0 +1,27 @@
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var member := 1
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func test():
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var number := 1
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var string := "1"
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var vector := Vector2i(1, 0)
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var array_assign := [1]
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var array_append := [1]
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var f := func ():
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member = 2
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number = 2
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string += "2"
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vector.x = 2
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array_assign = [2]
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array_append.append(2)
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var g := func ():
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member = 3
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number = 3
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string += "3"
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vector.x = 3
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array_assign = [3]
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array_append.append(3)
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prints("g", member, number, string, vector, array_assign, array_append)
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g.call()
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prints("f", member, number, string, vector, array_assign, array_append)
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f.call()
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prints("test", member, number, string, vector, array_assign, array_append)
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@@ -0,0 +1,36 @@
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GDTEST_OK
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>> WARNING
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>> Line: 11
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>> CONFUSABLE_CAPTURE_REASSIGNMENT
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>> Reassigning lambda capture does not modify the outer local variable "number".
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>> WARNING
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>> Line: 12
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>> CONFUSABLE_CAPTURE_REASSIGNMENT
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>> Reassigning lambda capture does not modify the outer local variable "string".
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>> WARNING
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>> Line: 13
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>> CONFUSABLE_CAPTURE_REASSIGNMENT
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>> Reassigning lambda capture does not modify the outer local variable "vector".
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>> WARNING
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>> Line: 14
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>> CONFUSABLE_CAPTURE_REASSIGNMENT
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>> Reassigning lambda capture does not modify the outer local variable "array_assign".
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>> WARNING
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>> Line: 18
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>> CONFUSABLE_CAPTURE_REASSIGNMENT
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>> Reassigning lambda capture does not modify the outer local variable "number".
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>> WARNING
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>> Line: 19
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>> CONFUSABLE_CAPTURE_REASSIGNMENT
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>> Reassigning lambda capture does not modify the outer local variable "string".
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>> WARNING
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>> Line: 20
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>> CONFUSABLE_CAPTURE_REASSIGNMENT
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>> Reassigning lambda capture does not modify the outer local variable "vector".
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>> WARNING
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>> Line: 21
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>> CONFUSABLE_CAPTURE_REASSIGNMENT
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>> Reassigning lambda capture does not modify the outer local variable "array_assign".
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g 3 3 123 (3, 0) [3] [1, 2, 3]
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f 3 2 12 (2, 0) [2] [1, 2, 3]
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test 3 1 1 (1, 0) [1] [1, 2, 3]
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@@ -9,6 +9,7 @@ func four_parameters(_a, callable : Callable, b=func(): print(10)):
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func test():
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var v
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@warning_ignore("confusable_capture_reassignment")
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v=func():v=1
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if true: v=1
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print(v)
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