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Add a script method to get its class icon
Co-authored-by: Danil Alexeev <danil@alexeev.xyz>
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@@ -482,6 +482,10 @@ void GDScript::_clear_doc() {
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docs.clear();
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doc = DocData::ClassDoc();
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}
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String GDScript::get_class_icon_path() const {
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return simplified_icon_path;
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}
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#endif
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bool GDScript::_update_exports(bool *r_err, bool p_recursive_call, PlaceHolderScriptInstance *p_instance_to_update) {
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@@ -2527,13 +2531,6 @@ String GDScriptLanguage::get_global_class_name(const String &p_path, String *r_b
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* Before changing this function, please ask the current maintainer of EditorFileSystem.
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*/
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if (r_icon_path) {
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if (c->icon_path.is_empty() || c->icon_path.is_absolute_path()) {
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*r_icon_path = c->icon_path.simplify_path();
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} else if (c->icon_path.is_relative_path()) {
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*r_icon_path = p_path.get_base_dir().path_join(c->icon_path).simplify_path();
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}
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}
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if (r_base_type) {
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const GDScriptParser::ClassNode *subclass = c;
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String path = p_path;
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@@ -2601,6 +2598,9 @@ String GDScriptLanguage::get_global_class_name(const String &p_path, String *r_b
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}
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}
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}
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if (r_icon_path) {
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*r_icon_path = c->simplified_icon_path;
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}
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return c->identifier != nullptr ? String(c->identifier->name) : String();
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}
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